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Thanks heaps Allan. I'm equally grateful for your answer, and solution, as I am to you trying to give me an out for what was indeed my stupidity :smile: Thanks so much to both yourself, Allan, and also Colin, much appreciated.

No. But your own above won't work with print either I'm afraid. Allan

That's not really something that DataTables itself does. You'd need a page which contains a DataTable that is populated by a conditional SELECT query (e.g. a WHERE statement). That condition would be the user name or id or something else depending on the structure of your database. The think to think about here is not how DataTables will do that for you, but rather how to do it without DataTables (i.e. a plain HTML) and then use DataTables to enhance that table. Allan

how can i deselect page 2 by this current page is 1.

okay i understood

The correct solution is: we made a slight change and we got a data Table Thank you!!! :) var $table = $('#example').DataTable({ 'ajax': { "type": "POST", "url": "http://localhost/ajax/thi/min.json", "dataType": 'json', "dataSrc": function (json) { console.log(json.data[0].hits.hits); var response_data1 = []; for (var i = 0; i < json.data[0].hits.hits.length; i++) { response_data1.push({ 'Name': json.data[0].hits.hits[i].sourceAsMap.name, 'Age': json.data[0].hits.hits[i].sourceAsMap.age, 'Date': json.data[0].hits.hits[i].sourceAsMap.date }) } console.log(response_data1); return response_data1; } }, "columns": [{ "data": "Name" }, { "data": "Age" }, { "data": "Date" } ] });

Hi @"Goutham.kn" , A quick search found this Medium page here . Hope that helps, Cheers, Colin

I'm not clear why the row id for the newly created row wouldn't be returned at the moment if you are using the PHP libraries for Editor? Could you elaborate on that for me? Thanks, Allan

the advantage of mine was that it had the creation of dynamic checkboxes and considering my use, I need them.

Hi @nordike , This thread here may be interesting, it shows how to move table elements to other locations. The other option is to do something in the CSS, like this here. Cheers, Colin