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Hi John, I just initialised the DataTable on your page with table = jQuery('#table_id').DataTable() See the attached screenshot: So there may be a conflict with the $ - see this StackOverflow thread. Hope that helps, Cheers, Colin

Hi @inquisitive_stha , You could run that same initialisation code again, but with destroy set to true, that way it'll recreate the table for you. Cheers, Colin

this: $('#table').DataTable().order([columnToSort, sortOrder]).draw(); Where: #table -> your table selector columnToSort

BY id DESC '; } MYSQL table structure :-- Field Type Null

the data to the table then viewModel.dataTableItems initializes the

Ok. Thx. Agree. But i did see the constructs of yadcf to define and customise columns of the table- a little different than normal datatables and hence was considering the porting effort.

it appears in the table. As I said, you

select elements in the table would be the way

and rendered to the table. when i have given

@colin So is it not possible to do it under every single column? Because my table would require calculation for all columns.