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8th column in the table itself and then add

would just insert the table in the second position.

go up for each table right? so.. $('#t0).dataTable() has

i could solve this problem. For each table i create object [code] oTable0 = $('#table0').dataTable(); oTable1 = $('#table1').dataTable(); [/code] and redraw function [code] $('#'+elm.id).mouseout( function() { oTable0.fnDraw(); } ); $('#'+elm.id).mouseout( function() { oTable1.fnDraw(); } ); [/code]

Any other thoughts on this? I cannot figure out how DataTables figures out the column widths. The table is small, so there is plenty of room for it to expand. Why is the last column wrapping?

have to destroy the table once you do what

is loaded on the table. 2. If you refresh

like this: [code] var table = $('.dataTable').dataTable( { "bJQueryUI": true, "bAutoWidth":

how filter and sort on head table?

If you initialise more than one table at a time, into oTable, then yes it is an array. You can use $.fn.dataTableExt.iApiIndex to change which table the API function you are using will operate on. Allan