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ajax.dataSrc is probably the one you want rather than ajax.data (which is before the

had the following in ajax.data: $.each( values, function ( name,

row. You can use ajax.data to do so, or

@"Tom (DataTables)" Thank you SO much for your reply. I was able to successfully use the ajax.dataSrc option to filter out certain items from the json array data before it's rendered (using the jQuery grep function). You saved me...thank you!

source. As you using ajax.data to submit as JSON

json_encode( $data ); Then use ajax.json() to access the JSON

causes information from the ajax/json to populate a form

can be controlled using ajax.dataSrc and, in this case,

would need to use ajax.data to submit the extra

records), and also use ajax.dataSrc set to an empty