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source. As you using ajax.data to submit as JSON

json_encode( $data ); Then use ajax.json() to access the JSON

causes information from the ajax/json to populate a form

can be controlled using ajax.dataSrc and, in this case,

would need to use ajax.data to submit the extra

records), and also use ajax.dataSrc set to an empty

Use ajax.data to convert or modify the data being sent to the server. Allan

There are examples on the ajax.data reference page that show how to do it - just scroll down the page to see the examples. See also this live example. Allan

I modified my script to use ajax.url & ajax.dataSrc for use after myTable.reload and with that, that's work.

I select no values, ajax.data: function (d) { d.select = $('.select-status').val();