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Is showing a Javascript error. That appears to be because the HTML defines only one column, but the Javascript is defining two for the #sites table. If you add another column to the HTML that should a

$(document).ready(function() { var siteEditor = new $.fn.dataTable.Editor( { ajax: "php/table.sites2.php", table: "#sites", fields: [ {

$(document).ready(function() { var siteEditor = new $.fn.dataTable.Editor( { ajax: "php/table.sites2.php", table: "#sites", fields: [ {

$(document).ready(function() { var siteEditor = new $.fn.dataTable.Editor( { ajax: "php/table.sites2.php", table: "#sites", fields: [ {

$(document).ready(function() { var siteEditor = new $.fn.dataTable.Editor( { ajax: "php/table.sites2.php", table: "#sites", fields: [ {

ajax: 'php/table.sites.php', table: '#sites', fields: [ { "label": "name:", "name": "name"

var editor = new $.fn.dataTable.Editor( { ajax: 'php/table.sites.php', table: '#sites', fields: [ { "label": "name:",

searchPane: { container: '#searchPanes', columns: [':contains("Division")', ':contains("Subdivision")'], thresho

and draw table function testDraw(dt){ $('#samples').DataTable().search('').draw(); if($(row.node()).find('select').length){ writeCell($(row.node()).find('select')); }

function(d) { d.start_date = $('#start-datepicker').val(); d.end_date = $('#end-datepicker').val(); }, "dataSrc" : "",

var table = $('#scraped')

The console was showing this when using the Select Default button:

$(document).ready(function () { var mainTable = $('#salesData').DataTable({ responsive: true, paging: false, info: false, fi

$('#samples').on('click', '#select_all', function() { if ($('#select_all:checked').val() === 'on') { dataTable.rows().select(); } else { dataTable.rows().deselect(); }

{ text: 'Select Default Library 1', action: function (e, dt, node, conf) { var rowSelector = [ '#sampleid_10', '#sampleid_2', '#sampleid_401' ]; var row1 = dataTable.rows(rowSel

{ text: 'Select Default Library 1', action: function (e, dt, node, conf) { var rowSelector = [ '#sampleid_10', '#sampleid_2', '#sampleid_401' ]; var row1 = dataTable.rows(rowSel

var compNumber = $('#compeititorNumber').val(); var score = $('#score').val(); var rowIdx = table .row( function ( idx, data, node ) { return data.compeititorNumber == compNumber; } ) .inde

my solution is here https://datatables.net/faqs/#speed, i have

var t = $('#statisticsTable').DataTable({ "paging": false, "ordering":false, "info":false, dom:'Bfrtip',

// Read values var name = $('#searchByName').val(); // Append to data data.searchByName = name; }, error: f