function on server side generated table

cmooz

hi,
i want to use this http://cssglobe.com/post/1695/easiest-tooltip-and-image-preview-using-jquery

in my server side generated table but it does only work outside the table

code is okay, what can i do to get this running?

allan

Hi cmooz,

Have a look at this thread: http://datatables.net/forums/comments.php?DiscussionID=187 . There are a number of other links in that thread which might be useful.

Allan

cmooz

i solved it while adding another fnDrawCallback

now it looks like this:

"fnRowCallback": function( nRow, aData, iDisplayIndex ) {
var $cell=$('td:eq(3)', nRow);
$cell.text(ellipsis($cell.text(),25));
return nRow;

},

"fnDrawCallback": fnOpenClose,
"fnDrawCallback": fnShowPic,

but the openclose is not working any more, when i change order of openclose & showpic always that one which is standing in last line works, the other not

any idea?

allan

Well you can't have two properties called the same thing ;-)

How about something like:

"fnDrawCallback": function (a,b,c) {
fnOpenClose(a,b,c);
fnShowPic(a,b,c);
}

Allan

cmooz

well,

"fnRowCallback": function( nRow, aData, iDisplayIndex ) {
var $cell=$('td:eq(3)', nRow);
$cell.text(ellipsis($cell.text(),25));
return nRow;
fnShowPic( nRow, aData, iDisplayIndex );
fnOpenClose( nRow, aData, iDisplayIndex );
},

does not work... nothing happens

i tried to add this to my image for opening the details table



it seems to work but i do have to click 3times for first opening and 2 time for closing and opening again

any idea to solve this problem?

thanks

allan

You've got unreachable code!

The fnShowPic() and fnOpenClose() functions aren't ever going to run there because there is a return statement in front of them! Try putting the return statement at the end of the function :-)

Allan