datatables - hidden row to query a different table for data based on first table (row) value

datatables - hidden row to query a different table for data based on first table (row) value

paulrodpaulrod Posts: 6Questions: 0Answers: 0
edited November 2010 in General
Hi,

I have a page that selects data from a company table. The results are displayed and datatables styles the data with no issue. However - I wish to use the hidden row option in datatables to query a second table called customers based on the value of , in this case column 1 (aData[1]).

I modified using the samples i found on your site a function called fnFormatDetails() that draws the second table (the hidden row) and post out via ajax post the url/parameters i need. I can see them post in firebug and my response back from a php script. However I cannot for the life of me figure out how to get this data to populate the fnFormDetails table.

My knowledge of jquery/ajax is limited. I am just starting on this. PHP I am ok on.

Thank you very much!
Paul

Replies

  • paulrodpaulrod Posts: 6Questions: 0Answers: 0
    sent a payment for your help. notes attached to payment, with further questions regarding your time. Thank you!
  • allanallan Posts: 63,400Questions: 1Answers: 10,452 Site admin
    Hi paulrod,

    Thanks for the donation :-). fnOpen returns the TR element that it creates - so what you could do (assuming I've understood correctly) is something like this:

    [code]
    var newRow = oTable.fnOpen( nTr, fnFormatDetails(oTable, nTr), 'details' );

    $.ajax( {
    "dataType": 'json',
    "type": "POST",
    "url": sSource,
    "data": aoData,
    "success": function ( json ) {
    $('td', newRow).html( json.htmlParameter );
    }
    } );
    [/code]
    You could write "loading" into the cell for while the Ajax is going on as well to make it clear what is happening :-)

    Regards,
    Allan
  • paulrodpaulrod Posts: 6Questions: 0Answers: 0
    Allan,
    Thank you I will try this. So I am changing your example code to open the table from;

    /* Open this row */
    this.src = "_img/details_close.png";
    oTable.fnOpen( nTr, fnFormatDetails(oTable, nTr), 'details' );

    to

    this.src = "_img/details_close.png";
    var newRow = oTable.fnOpen( nTr, fnFormatDetails(oTable, nTr), 'details' );

    and in the fnFormatDetails function i am inserting the ajax call?

    Thanks
    Paul
  • paulrodpaulrod Posts: 6Questions: 0Answers: 0
    if this goes in the fnFormatDetails function how do I get the results into sOut to be returned?
  • paulrodpaulrod Posts: 6Questions: 0Answers: 0
    just to clarify;

    I now have the following;

    [code]
    $('#example tbody td img').live('click', function ()
    {
    var nTr = this.parentNode.parentNode;
    if ( this.src.match('details_close') )
    {
    /* This row is already open - close it */
    this.src = "_img/details_open.png";
    oTable.fnClose( nTr );

    } else{
    /* Open this row */
    this.src = "_img/details_close.png";
    //oTable.fnOpen( nTr, fnFormatDetails(oTable, nTr), 'details' );
    var newRow = oTable.fnOpen( nTr, fnFormatDetails(oTable, nTr), 'details' );

    }
    } );
    [/code]

    so where in here is the ajax call?

    [code]
    function fnFormatDetails ( oTable, nTr )
    {
    var aData = oTable.fnGetData( nTr );
    var sOut = '';
    sOut += 'Rendering engine:'+aData[1]+' '+aData[11]+'';
    sOut += 'Link to source:Could provide a link here';
    sOut += 'Extra info:And any further details here (images etc)';
    sOut += '';
    sOut += '';
    return sOut;
    }
    [/code]

    the php will grab from the ajax post the value in aData[1] and pull up a series of records. I need to return those records back. I suppose the records returned from the php script will have to be json formated (var:val) ? If thats the case then this function will need to parse out and create the table rows for each record. not sure how.

    thanks again!
  • paulrodpaulrod Posts: 6Questions: 0Answers: 0
    edited November 2010
    sorry to keep posting, but i think i figured it out. i now have;

    [code]
    this.src = "_img/details_close.png";
    //oTable.fnOpen( nTr, fnFormatDetails(oTable, nTr), 'details' );
    sID = fnFormatDetails(oTable, nTr)

    var newRow = oTable.fnOpen( nTr,
    $.ajax( {
    dataType: 'json',
    type: "POST",
    url: "processor.php",
    data: "custid="+sID,
    success: function ( json ) {
    var tableHead = '';
    $('td', newRow).html('Company IDempl_fnameempl_lnameempl_titleempl_phoneempl_faxempl_cell'+ json.postsuccess.................+'' );}} ), 'details' );

    }
    } );
    [/code]

    [code]function fnFormatDetails ( oTable, nTr )
    {
    var aData = oTable.fnGetData( nTr );
    return aData[1];
    }
    [/code]
  • allanallan Posts: 63,400Questions: 1Answers: 10,452 Site admin
    Yup that looks like to should work okay (although I don't know what $.ajax() returns... whatever it is, DataTables will be writing it into the cell...). I think I personally would have done something a little bit more like this:

    [code]
    var newRow = oTable.fnOpen( nTr, "Loading data..." );
    $.ajax( {
    dataType: 'json',
    type: "POST",
    url: "processor.php",
    data: "custid="+sID,
    success: function ( json ) {
    ... process for html
    $('td', newRow).html( newHTML );
    }
    } );
    [/code]
    As it allows a 'loading' indicator to be put into the cell while the XHR is off getting the new data :-)

    Regards,
    Allan
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