Answers

• kthorngren Posts: 22,354Questions: 26Answers: 5,137

  February 2020

  You can use the row parameter to get the tr element. I've used columns.className to add a class to the rendered column I want to check and in createdRow used var status = $(row).find('.status').text(); to get the text of that particular cell. The rendered column is not part of the row data source which is why it isn't accessible using the data parameter.

  Kevin
• mihalisp Posts: 127Questions: 22Answers: 0

  February 2020

  Thank you.
  But what if i also have another class for that column?
  eg."className": 'text-center', "targets": [8,9,10,11,12,13,14] } and "className": 'status', "targets": [8] }

  In this case only one class works.It does not 'center' the text in the column.

     if ($(row).find('.status').text()  < 0 )  {  
  
      $(row).find('.status').css('color', 'red');
      }
  
• kthorngren Posts: 22,354Questions: 26Answers: 5,137

  February 2020 Answer ✓

  The second will likely overwrite the first. You can add multiple classNames in one string, like this: "className": 'text-center status', "targets": [8,9,10,11,12,13,14] }. The same as you would add directly in HTML.

  Kevin
• mihalisp Posts: 127Questions: 22Answers: 0

  February 2020

  I use

   if ($(row).find('.text-center .status').text()  < 0 )  { 
  
   $(row).find('.text-center .status').css('color', 'red');
    }
  

  but id does not work.

  How should the if ($(row).find(' ') be written?
• mihalisp Posts: 127Questions: 22Answers: 0

  February 2020

  There must be no space between the 2 classes in order to work.

    $(row).find('.text-center.status').css('color', 'red');
  

  Thank you.
• kthorngren Posts: 22,354Questions: 26Answers: 5,137

  February 2020

  You should be able to use just .status, like this:
  $(row).find('.status').css('color', 'red');

  Unless of course you want to limit the find to having both.

  Kevin