Answers

• jhonny14 Posts: 5Questions: 2Answers: 0

  February 2016

  i have made it work with this:

  { data: "files", render: function ( data, type, full ) {
    return $.map( data, function ( d, i ) {
      return '<img alt="'+ d.filename +'" src="'+ d.web_path +'" width="24px"/>';
    } ).join( ' ' );
  }
  

  but i dont understand why with .each doesnt work

  { data: "files", render: function ( data, type, full ) {
    return $.each( data, function ( d, i ) {
      return '<img alt="'+ d.filename +'" src="'+ d.web_path +'" width="24px"/>';
    } );
  }
  
• allan Posts: 63,204Questions: 1Answers: 10,415 Site admin

  February 2016 Answer ✓

  I used this code but it says: "TypeError: table.file(...) is undefined"

  That would happen if you are using an old version of Editor or you used the $().dataTable() constructor rather than $().DataTable(). The file() method was introduced in Editor 1.5.

  The $.each method doesn't work, because $.each doesn't do anything with the return. The jQuery documentation says:

  The method returns its first argument, the object that was iterated.

  Allan
• jhonny14 Posts: 5Questions: 2Answers: 0

  February 2016

  so i am using: /*! DataTables Editor v1.5.4
  and the constructor: var table = $('#concesiune').DataTable( {

  .each method should return this:

   return '<img alt="'+ d.filename +'" src="'+ d.web_path +'" width="24px"/>';
  

  it should do for the lenght of data iterate and return the code above

  sorry for my poor knowledge
• allan Posts: 63,204Questions: 1Answers: 10,415 Site admin

  February 2016

  Are you able to give me a link to the page so I can debug it it and see what is going on?

  Having said that, if the $.map method is working for you - go with that. That is a correct way to do it.

  Allan