Answers

• Tom (DataTables) Posts: 139Questions: 0Answers: 26

  May 2016

  Hi STKenneth

  I believe when searching columns by index you have to refer to the column starting from 1 not 0.

  So if you wanted to select the last column from the image you posted you would use 4 not 3 as menu is a column as well.

  Thanks,

  Tom
• STKenneth Posts: 7Questions: 3Answers: 0

  May 2016

  Hello Tom,

  Thank you for your reply.

  In my second photo, I have tried to use 3 in columns and then do search but it does not work. How do I debug that? Is there any way to check that.
• STKenneth Posts: 7Questions: 3Answers: 0

  June 2016 edited June 2016

  Hello Tom

  Please see the photo. Search function did not work for the last column
  https://goo.gl/photos/UMxakt5dp74BXRpg7

  My code

  var filterhtml ='';
  var ths = $('#table_id thead th');
  for(var i = 0, j= ths.length; i< j; i++)
  {
  var title = ths[i].textContent;
  if(title =="Menu")
  {
  filterhtml +='<th></th>';
  }
  else{
  filterhtml +='<th><input type="text" accessKey="'+(i+1)+'" data-index="'+(i+1)+'" placeholder="Search '+title+'" /></th>';
  }
  }
  
  var that = $('#table_id_wrapper thead').first();
  $("<thead id='individualfilter'><tr>"+filterhtml+"</tr></thead>").insertBefore( that);
  
  table.columns().every( function () {
  var that = this;
  $( 'input', $("#individualfilter th") ).on( 'keyup change', function () {
  if ( that.search() !== this.value ) {
  that
  .columns(this.accessKey)
  .search( this.value )
  .draw();
  }
  } );
  } );
• STKenneth Posts: 7Questions: 3Answers: 0

  June 2016

  Hello Tom,

  I think I already solve this issue after upgrading to 1.10.12.

  The previous version is 1.10.8.

  Thank you for your reply.
• Tom (DataTables) Posts: 139Questions: 0Answers: 26

  June 2016

  Hi Kenneth

  Thanks for the update, glad you got it working.

  Tom