Server Side Processing + Show/ Hide

Server Side Processing + Show/ Hide

ESHamESHam Posts: 14Questions: 0Answers: 0
edited December 2013 in DataTables 1.9
Hello I am trying to get show hide to work with server side. I get "Requested Unknown Parameter".
[code]
<?php

$aColumns = array( 'accountid', 'accountname', 'accountAddress1', 'accountphone', 'accountemail');

$sIndexColumn = "accountname";

/* DB table to use */
$sTable = "accounts";

/* Database connection information */
$gaSql['user'] = "XX";
$gaSql['password'] = "";
$gaSql['db'] = "XX";
$gaSql['server'] = "XX";

/* Local functions*/

function fatal_error ( $sErrorMessage = '' )
{
header( $_SERVER['SERVER_PROTOCOL'] .' 500 Internal Server Error' );
die( $sErrorMessage );
}
/*
* MySQL connection
*/
if ( ! $gaSql['link'] = mysql_pconnect( $gaSql['server'], $gaSql['user'], $gaSql['password'] ) )
{
fatal_error( 'Could not open connection to server' );
}

if ( ! mysql_select_db( $gaSql['db'], $gaSql['link'] ) )
{
fatal_error( 'Could not select database ' );
}


/*
* Paging
*/
$sLimit = "";
if ( isset( $_GET['iDisplayStart'] ) && $_GET['iDisplayLength'] != '-1' )
{
$sLimit = "LIMIT ".intval( $_GET['iDisplayStart'] ).", ".
intval( $_GET['iDisplayLength'] );
}
/*
* Ordering
*/
$sOrder = "";
if ( isset( $_GET['iSortCol_0'] ) )
{
$sOrder = "ORDER BY ";
for ( $i=0 ; $i $iFilteredTotal,
"aaData" => array()
);

while ( $aRow = mysql_fetch_array( $rResult ) )
{
$row = array();

for ( $i=0 ; $i
[/code]
My HTML
[code]




Rendering engine
Browser
Platform(s)
Engine version
CSS grade




Loading data from server





Rendering engine
Browser
Platform(s)
Engine version
CSS grade




[/code]
Finally My Script:
[code]

function fnFormatDetails ( oTable, nTr )
{
var aData = oTable.fnGetData( nTr );
var sOut = '';
sOut += 'Rendering engine:'+aData[1]+' '+aData[4]+'';
sOut += 'Link to source:Could provide a link here';
sOut += 'Extra info:And any further details here (images etc)';
sOut += '';

return sOut;
}

$(document).ready(function() {
/*
* Insert a 'details' column to the table
*/
var nCloneTh = document.createElement( 'th' );
var nCloneTd = document.createElement( 'td' );
nCloneTd.innerHTML = '';
nCloneTd.className = "center";

$('#example thead tr').each( function () {
this.insertBefore( nCloneTh, this.childNodes[0] );
} );

$('#example tbody tr').each( function () {
this.insertBefore( nCloneTd.cloneNode( true ), this.childNodes[0] );
} );

/*
* Initialse DataTables, with no sorting on the 'details' column
*/
var oTable = $('#example').dataTable( {
"aoColumnDefs": [
{ "bSortable": false, "aTargets": [ 0 ] }
],
"aaSorting": [[1, 'asc']],
"bProcessing": true,
"bServerSide": true,
"sAjaxSource": "CJS/Myjson.php",

"aoColumns": [
{ "sClass": "center", "bSortable": false },
null,
null,
null,
{ "sClass": "center" },
{ "sClass": "center" }
],

});

$('#example tbody td img').live('click', function () {
var nTr = this.parentNode.parentNode;
if ( this.src.match('details_close') )
{
/* This row is already open - close it */
this.src = "assets/advanced-datatable/examples/examples_support/details_open.png";
oTable.fnClose( nTr );
}
else
{
/* Open this row */
this.src = "assets/advanced-datatable/examples/examples_support/details_close.png";
oTable.fnOpen( nTr, fnFormatDetails(oTable, nTr), 'details' );
}
} );
} );

[/code]

Replies

  • allanallan Posts: 63,494Questions: 1Answers: 10,470 Site admin
    Please link to a test page, showing the issue as noted in the forum rules: http://datatables.net/forums/discussion/12899

    Allan
  • ESHamESHam Posts: 14Questions: 0Answers: 0
    Alan, I am new to coding.. but i saved a test page on http://live.datatables.net/apasez/2/edit#javascript,html
  • allanallan Posts: 63,494Questions: 1Answers: 10,470 Site admin
    I'm getting errors on the page I'm afraid: ReferenceError:` Can't find variable: $` for example. Can you link me to the page you are working on, or one with the required resources included.
  • ESHamESHam Posts: 14Questions: 0Answers: 0
    Allan, Thanks for getting back.
    You can view my table via http://207.38.165.173:5555/flatlap/accountsTest.php

    Thanks for the help in advance.
  • allanallan Posts: 63,494Questions: 1Answers: 10,470 Site admin
    Sorry - my browser says that the server is not available. Is it online at the moment?
  • ESHamESHam Posts: 14Questions: 0Answers: 0
    Allan,
    It should be up now.
  • allanallan Posts: 63,494Questions: 1Answers: 10,470 Site admin
    The table header has 7 columns
    The table body as 6 columns
    The Ajax data arrays for each row has 5 elements

    They should all match. Which one is correct?
  • ESHamESHam Posts: 14Questions: 0Answers: 0
    i want the header to have 6 columns.. same thing for the body.
    As for the Ajax, i will be returning additional columns to be viewed when the details icon on the first row is opened.
  • allanallan Posts: 63,494Questions: 1Answers: 10,470 Site admin
    Excellent - I'd suggest making those modifications then :-). Just have 6 columns in the header and use mData / mRender in aoColumns to tell DataTables what data to show for each column.

    Allan
  • ESHamESHam Posts: 14Questions: 0Answers: 0
    Allan, I am not sure where you see the header 7 Columns..
    this is what i have for columns
    [code]



    Rendering engine
    Browser
    Platform(s)
    Engine version
    CSS grade



    [/code]
  • ESHamESHam Posts: 14Questions: 0Answers: 0
    Allan.
    I changed the script to the one below, i am now getting the extra column for the details but the page merges to the left and leaves the last defined column empty, and no details on the first column.
    [code]
    $(document).ready(function() {
    /*
    * Insert a 'details' column to the table
    */
    var nCloneTh = document.createElement( 'th' );
    var nCloneTd = document.createElement( 'td' );
    nCloneTd.innerHTML = '';
    nCloneTd.className = "center";

    $('#example thead tr').each( function () {
    this.insertBefore( nCloneTh, this.childNodes[0] );
    } );

    $('#example tbody tr').each( function () {
    this.insertBefore( nCloneTd.cloneNode( true ), this.childNodes[0] );
    } );

    /*
    * Initialse DataTables, with no sorting on the 'details' column
    */
    var oTable = $('#example').dataTable( {
    "aoColumnDefs": [
    { "bSortable": false, "aTargets": [ 0 ] }
    ],
    "aaSorting": [[1, 'asc']],
    "bProcessing": true,
    "bServerSide": true,
    "sAjaxSource": "CJS/accountsjson.php",
    "aoColumns": [
    { "mData": "0" },
    { "mData": "1" },
    { "mData": "2" },
    { "mData": "3" },
    { "mData": "4" }
    ]

    });

    /* Add event listener for opening and closing details
    * Note that the indicator for showing which row is open is not controlled by DataTables,
    * rather it is done here
    */
    $('#example tbody td img').live('click', function () {
    var nTr = this.parentNode.parentNode;
    if ( this.src.match('details_close') )
    {
    /* This row is already open - close it */
    this.src = "assets/advanced-datatable/examples/examples_support/details_open.png";
    oTable.fnClose( nTr );
    }
    else
    {
    /* Open this row */
    this.src = "assets/advanced-datatable/examples/examples_support/details_close.png";
    oTable.fnOpen( nTr, fnFormatDetails(oTable, nTr), 'details' );
    }
    } );
    } );

    [/code]
  • allanallan Posts: 63,494Questions: 1Answers: 10,470 Site admin
    Server is offline again.

    However, if you have 6 columns and want 6 columns, why are there only 5 in your aoColumns array?

    Allan
  • ESHamESHam Posts: 14Questions: 0Answers: 0
    I would like the table to return 5 columns.. and the extra column is created automatically to include the details (+) which drop downs to another table.
  • ESHamESHam Posts: 14Questions: 0Answers: 0
    Allan, I am sorry to keep bothering you. but this is driving me crazy..
    i was able to have the details icon show up on the first column briefly until i hit ok on (Requested Unknown parameter 5) i only see 5 Header in my table, and returning 5 objects from the array.. how do i go about adding the details column that opens the drop down table. Let me know what you think.
  • ESHamESHam Posts: 14Questions: 0Answers: 0
    Thanks.. i was able to solve it by inserting an extra column in the array
    [code]
    $row[] = '';
    [/code]

    Thank you so much for your help.. i am sure i will be back here very soon with another newbie question :) .
This discussion has been closed.