Trying to using ajax to fill child rows.

Trying to using ajax to fill child rows.

rbyrnsrbyrns Posts: 36Questions: 9Answers: 0
edited December 2014 in DataTables 1.10

I decided that is was better to get my notes from a separate ajax call.
I have the function:

function format ( notes ){
            //var noteArray = notes;   //used to be notes.notes
            if(notes.length === 0){ return "<td>No Notes Found</td>"};
            console.log(notes.length);
            var i = 0;
            var len = notes.length;
            var out;
            for(;i<len; i++){
                out += '<tr><td>'+notes[i].type+'</td><td>'+notes[i].note+'</td></tr>'
            }
            return out;
      };

Below I have this:

    var detailRows = []; //sub row stuff
    $('#vert_test tbody').on('click','td.details-control', function(){
    var tr = $(this).closest('tr');
    var row = table.row( tr );
    var idx = $.inArray(tr.attr('id'), detailRows ); //??
    $.ajax({
        type:'GET',
        url: './php/table.vert_test.php?p=1',
        data: 'row='+tr.attr('id'),
    })
   
    if (row.child.isShown()){
    tr.removeClass('details');
    row.child.hide();
    
    // remove from the 'open' array
    detailRows.splice(idx,1); //??
    }
    else {
    tr.addClass('details');
    row.child(format(row.data())).show(); 
    //add to the open array
    if (idx=== -1){
        detailRows.push(tr.attr('id'));
    }
    }
    }); //end of click function

the ajax Get is firing, an array of notes is returning. Everything looks right, but the error is "TypeError: row.child(...) is undefined.

Answers

  • allanallan Posts: 63,498Questions: 1Answers: 10,471 Site admin

    but the error is "TypeError: row.child(...) is undefined.

    Are you using $().DataTable() to initialise the table? It sounds like you might be using $().dataTable() (note the difference in capitalisation) - FAQs.

    Regards,
    Allan

  • rbyrnsrbyrns Posts: 36Questions: 9Answers: 0
    edited December 2014

    This is my initialization code.

     editor = new $.fn.DataTable.Editor( {
            "ajax": "./php/table.vert_test.php",
            "idSrc": "uid",
            "table": "#vert_test",
                "stateSave":true,
                formOptions: {
                inline: {
                "submitOnBlur": "true", //true always when inline editing
                }
            },
            "fields": [
                {
                    "label": "SI Number",
                    "name": "sinum",
                    "type": "text"
                },
                {
                    "label": "Prefix",
                    "name": "prefix",
                    "type": "text"
    
    //more code in middle
    
        $('#vert_test').DataTable( {
            
            "jQueryUI": true,
            "scrollY":400,
            "scrollX": true,
            "dom": 'T<"clear">lfrtip',
            "lengthMenu":[[25, 50, 100],[25,50,100]],
            "ajax":{
                url: "./php/table.vert_test.php",
                type: "POST",
                "data": function (d){
                d.min = $('#min').val();
                d.max = $('#max').val();
                d.field = $("#field").val();  //extra data from parent form
                }
            },
    
            "bProcessing":true,
            "bServerSide": true,
            "bAutowidth": true,
            table: "#vert_test",
            formOptions: {
                inline: {
                    submitOnBlur: true
                }
            },
        
            "columns": [
            {
                "class":    ////etc...
    
  • rbyrnsrbyrns Posts: 36Questions: 9Answers: 0

    Because this ajax call is just for the child rows and not the entire table, do I need to use DataSrc?

  • allanallan Posts: 63,498Questions: 1Answers: 10,471 Site admin

    You con't appear to assign $('#vert_test').DataTable(...); to anything. So where does the table variable in the code in your previous post come from?

    Allan

  • rbyrnsrbyrns Posts: 36Questions: 9Answers: 0
    edited December 2014

    Sorry, didn't get that part.

        var table = $('#vert_test').DataTable();
        table.columns().eq( 0 ).each( function ( colIdx ) {
            $( 'input', table.column( colIdx ).footer() ).on( 'keyup change', function () {
                table
                .column( colIdx )
                .search( this.value )
                .draw();
            } );
        } );
        var detailRows = []; //sub row stuff
        $('#vert_test tbody').on('click','td.details-control', function(){
        var tr = $(this).closest('tr');
        var row = table.row( tr );
        var idx = $.inArray(tr.attr('id'), detailRows ); //??
        $.ajax({
            type:'GET',
            url: './php/table.vert_test.php?p=1',
            data: 'row='+tr.attr('id'),
        })
    
    
         
        if (row.child.isShown()){
        tr.removeClass('details');
        row.child.hide();
        
        // remove from the 'open' array
        detailRows.splice(idx,1); //??
        }
        else {
        tr.addClass('details');
        row.child(format(row.data())).show(); 
        //add to the open array
        if (idx=== -1){
            detailRows.push(tr.attr('id'));
        }
        }
        }); //end of click function
    
        // on each draw loop over the detailsRows and show any children
        editor.on('draw', function (){
            $('#'+id+'td:first-child').trigger('click');
        });
    //// date range stuff
       $( "#min" ).datepicker( {
           "dateFormat": "yy-mm-dd",
        "onSelect": function(date) {
          min = new Date(date).getTime();
          table.draw();
        }
      } ).keyup( function () {
          var min= new Date(this.value).getTime();
          table.draw();
      } );
      
      $( "#max" ).datepicker( {
           "dateFormat": "yy-mm-dd",
        "onSelect": function(date) {
          var max = new Date(date).getTime();
          if(min != ''){ table.draw()};
        }
      } ).keyup( function () {
          max = new Date(this.value).getTime();
          table.draw();
      } );
    $("#field").on('change',function(){
        table.draw();
    });
          // end date range stuff 
     
    //end displayTable functions 
    //
    } );
    

    }(jQuery));

  • allanallan Posts: 63,498Questions: 1Answers: 10,471 Site admin

    Okay, that looks like it should probably work. I think I'd need a link to the page to see the error "in action" to be able to offer any help with it I'm afraid.

    Allan

  • rbyrnsrbyrns Posts: 36Questions: 9Answers: 0
    edited December 2014

    I pm'd you the link

  • rbyrnsrbyrns Posts: 36Questions: 9Answers: 0

    For anyone else dealing with this issue: The following is my solution.

    var detailRows = []; //sub row stuff
     
    $('#vert_test tbody').on('click','td.details-control', function(){
    var tr = $(this).closest('tr');
    var idx = $.inArray(tr.attr('id'), detailRows ); //??
    var row = table.row( tr );
        $.ajax({
        type:'GET',
        url: './php/table.vert_test.php?p=1',
        data: 'row='+tr.attr('id'),
            dataType: 'json',
        success: function(result){
            if (row.child.isShown()){
                tr.removeClass('details');
                row.child.hide();
                // remove from the 'open' array
                detailRows.splice(idx,1); //??
            }
            else {
                tr.addClass('details');
                row.child(format(result)).show();
                //add to the open array
                if (idx=== -1){
                    detailRows.push(tr.attr('id'));
                }
            }
     
        }
    });
      
    }); //end of click function
    

    The "format" function is

    function format ( notes ){
                console.log(notes);
                var noteArray = notes.notes;   //used to be notes.notes
                if(noteArray.length === 0){ return "<td>No Notes Found</td>"};
                var i = 0;
                var len = noteArray.length;
                var out;
                for(;i<len; i++){
                out += '<tr><td>'+noteArray[i].type+'</td><td>'+noteArray[i].note+'</td></tr>'
    
                }
                return out;
          };
    

    The main issue is that ajax is asynchronous. Also take note of the dataType:json. Without it, it was treating the results as a string.

This discussion has been closed.