rows().columns().nodes().flatten().to$()

zapata

snc.a[s] contains title of TD. But I cant add each of title to each of 7th TD. BUT 7th TD always get value of last snc.a[s]

var newTable=$('#musteri_ara_table').DataTable({"bFilter" : false,"bLengthChange": false});$.ajax({
   type:"POST",
   url:"myUrl",
   data:"myData", 
   dataType:"json",
   success:function(snc){
        for(s=0;   s< snc.a.length;  s++){
           nod= newTable.row.add( [s+1,snc.a[s]]).draw();nod.rows(s).columns(6).nodes().flatten().to$().attr("title",s);}}

allan

Can you link to a test page showing the issue, as per the forum rules, please.

Thanks,
Allan

zapata

http://www.resge.com/test/dTable.php

As you will see, second column is red and its title is not that I want(Column Title has to be which artist's last name at each row). All second columns title is The last data Magic Johnson's last name.

allan

You need to use an iterator - at the moment you have the code setting the title attribute for all of the cells in column 1, and the last one will "win".

I would suggest using rows().every():

newTable.rows().every( function () {
  $( this.cell( this.index(), 1 ).node() ).attr( this.data()[2] );
} );

You will need to updated to 1.10.6 to use rows().every().

Allan

zapata

$( nod.cell(s,1).node() ) .attr("title",snc.lname[s]);
that is ok. thanks!