how to create ajax's datatables using 2 table of mysql?

how to create ajax's datatables using 2 table of mysql?

kommkomm Posts: 1Questions: 1Answers: 0
edited November 2015 in Free community support

Hi everyone,
i need to do a table using data of 2 (or more) tables of my database (mysql) using ajax and php obv.
for 1 table i'm using this code:

<?php
/*
 * DataTables example server-side processing script.
 *
 * Please note that this script is intentionally extremely simply to show how
 * server-side processing can be implemented, and probably shouldn't be used as
 * the basis for a large complex system. It is suitable for simple use cases as
 * for learning.
 *
 * See http://datatables.net/usage/server-side for full details on the server-
 * side processing requirements of DataTables.
 *
 * @license MIT - http://datatables.net/license_mit
 */
 
/* * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * *
 * Easy set variables
 */
 
// DB table to use
$table = 'table';
 
// Table's primary key
$primaryKey = 'primarykey';
 
// Array of database columns which should be read and sent back to DataTables.
// The `db` parameter represents the column name in the database, while the `dt`
// parameter represents the DataTables column identifier. In this case simple
// indexes
$columns = array(
    array( 'db' => 'cod', 'dt' => 0 ), 
    array( 'db' => 'description', 'dt' => 1 ),
    array(
        'db'        => 'date',
        'dt'        => 2,
        'formatter' => function( $d, $row ) {
            return date( 'Y/m/d', strtotime($d));
        }
    )


);
 
// SQL server connection information 
$sql_details = array(
    'user' => 'root',
    'pass' => '',
    'db'   => 'db',
    'host' => '127.0.0.1'
);
 
 
/* * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * * *
 * If you just want to use the basic configuration for DataTables with PHP
 * server-side, there is no need to edit below this line.
 */
 
require( 'ssp.class.php' );
 
 
 
 
echo json_encode(
    SSP::simple( $_GET, $sql_details, $table, $primaryKey, $columns )
);

anyone can help me? thanks so much!

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