About: Server-side processing Pls Help

demir

PHP

public function getDataStokSelect()
    {
        if ($_REQUEST) {
            $requestData= $_REQUEST;
            $columns = array(
                // datatable column index  => database column name
                0 =>'a',
                1 =>'b',
                2=> 'c',
                3=> 'd',
                4=> 'e',
                5=> 'f',
            );
            $id=$requestData['columns']['id']['data'];    // **If i can send it i can not catch it on the server side~~~~**
            $where= " `b` LIKE '".$id."%' ";
            $json=$this->fastDataTable($requestData,'views_stokTable',$columns,false,false);
            echo json_encode($json);
        }
    }

JS

function createLBTable(dataWay,columns,id="",tableName='data-table') {
 table = $('#'+tableName).DataTable({  
        "processing": true,
        "serverSide": true,
        "ajax":{
          url :base_url+dataWay, 
          type: "POST" ,   
          data:{'id':id}, //## I can not send an id here !!!!
          error: function(){ 
              $(".data-table-error").html("");
              $("#data-table").append('<tbody class="data-table-error"><tr><th colspan="3">No data found in the server</th></tr></tbody>');
              $("#data-table_processing").css("display","none");  
          }
        },
       "language": turkish,
       "columns":columns,
       "columnDefs": [
        {
          "className":'none',
          "targets": 0
        }]
 });
}

Normally I can get this feature on the server side.But I can not catch processing, serverSide when is true. How do I catch the id I send on php. Thank you for your time.

allan

data:{'id':id}, //## I can not send an id here !!!!

What is id at that point of you debug it or add a console.log immediately before your table initialisation.

Ideally we'd have a link to the page so we can debug it.

Allan