Use function as source in rowGroup.dataSrc()

JesterAntik

I'll try to use rowGroup. But when I add the data-sort attribute to a column, rowGroup does not work. As I understand it, this is due to the call to the dataFn, which I can not directly set.

allan

Could you show me the code you are using please? Or even better, a link to a test case showing the issue.

Thanks,
Allan

JesterAntik

I incorrectly set the task. I think you can close this discussion. I will open a new one with a statement of the problem in its original form and with an example.

JesterAntik

That's my fault. I use the construction from the example:

table.on( 'rowgroup-datasrc', function ( e, dt, val ) {
    table.order.fixed( {pre: [[ val, 'asc' ]]} ).draw();
} );
 
$('a.group-by').on( 'click', function (e) {
    e.preventDefault();
 
    table.rowGroup().dataSrc( $(this).data('column') );
} );

In this case have error:

Cannot read property 'aDataSort' of undefined

JesterAntik

It's my fault.
I use code from example:

table.on( 'rowgroup-datasrc', function ( e, dt, val ) {
    table.order.fixed( {pre: [[ val, 'asc' ]]} ).draw();
} );
function makeData(data, type, row, meta) {
  ....
}
$('a.group-by').on( 'click', function (e) {
    e.preventDefault();
    table.rowGroup().dataSrc( makeData );
} );

In this case I have error:

Cannot read property 'aDataSort' of undefined

Only now I realized that the problem with
table.order.fixed( {pre: [[ val, 'asc' ]]} ).draw();

JesterAntik

Sorry, it's my fault. I try to fix other issue by function, and take error at

table.on('rowgroup-datasrc', function (e, dt, val) {
dt.order.fixed({pre: [[val, 'asc']]}).draw();
}

where val is a function, not column index

JesterAntik

It's my fault.
I use code from example:

table.on( 'rowgroup-datasrc', function ( e, dt, val ) {
    table.order.fixed( {pre: [[ val, 'asc' ]]} ).draw();
} );
function makeData(data, type, row, meta) {
  ....
}
$('a.group-by').on( 'click', function (e) {
    e.preventDefault();
    table.rowGroup().dataSrc( makeData );
} );

In this case I have error:

Cannot read property 'aDataSort' of undefined

Only now I realized that the problem with
table.order.fixed( {pre: [[ val, 'asc' ]]} ).draw();