Create form depending on record(s) in other table

Create form depending on record(s) in other table

nklinkersnklinkers Posts: 24Questions: 4Answers: 0

Hello,

I want to check, when a user wants to create a new record in a table, if in another table there is minimal 1 record. When there are no records in the other table, I want to display a message so that the user first needs to create a record in that other table.
This because in the new to creating record, there should be a relation to the other table.

So also I want to check when a user wants to delete the record from the other table, that this is prohibited because it is used in the other table with the relation.

How should I do this?

Thank you in advance.
Noël

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Answers

  • allanallan Posts: 63,893Questions: 1Answers: 10,531 Site admin
    Answer ✓

    Sounds like an ideal case for a custom button. You would have the button's action function first check to see if the condition is satisfied or not - if not then show the error message. If it is then call the create() method to show the create form.

    Allan

  • nklinkersnklinkers Posts: 24Questions: 4Answers: 0

    Thanks for the direction. After some puzzling and looking at the examples it worked out for me.

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