Will the datatable reinitialize inside drawcallback?

NorwegianBlue

Hi

I'm trying to create a contextmenu with this plugin: http://swisnl.github.io/jQuery-contextMenu/index.html.

I need to use a the .row function on the very same table that I'm initializing inside the drawCallback. It works if I use the following: table.DataTable().row(this);, but will this reinitialize the table?

When I use table.row(this) I get the following error: Uncaught TypeError: table.row is not a function.

Here's the complete code:

`table.DataTable({
"columns": [
{"data": "id"},
{"data": "name"},
{"data": "created"},
{"data": "modified"},
],
"drawCallback": function () { // Adds contextmenu
jQuery.contextMenu({
selector: 'tbody tr td',
callback: function (key, options) {
var row = table.DataTable().row(this);
doCategoriesContextMenu(row, key);
},
"items": {
"1": {name: "Delete", icon: "delete"}

            }
        });
    },
    "pageLength": 10,
    "language": {
        "lengthMenu": "_MENU_ ",
        "search": "",
        "loadingRecords": "Loading...",
        "processing": "Processing...",
        "select-info": ""
    },
    "columnDefs": [
        {
            "targets": [0],
            "visible": false,
            "searchable": false
        },
    ],
    "responsive": true,
    "select": {
        style: 'single'
    },
    "order": [[0, "asc"]]
});`

Hope someone can help me

Edit: I've no idea why the entire code is not formatted above. I'm using the code formatting option in the editor, but it doesn't work. Hope it's readable.

kthorngren

I'm not sure what the variable table is but maybe if you change to specifying the table selector it might work. For example:

$('#myTable').DataTable().row(this);

Kevin

NorwegianBlue

Thanks for your answer.

The variable table is the my categories table: var table = $('#categories-table').

Your suggestion above works, but that I already knew. My question was if this will initalize the table twice, as the DataTable() function is called twice?

kthorngren

My question was if this will initalize the table twice, as the DataTable() function is called twice?

No, you are accessing a new API instance as described here:
https://datatables.net/manual/api#Accessing-the-API

Kevin

NorwegianBlue

Thanks. That's good