Pre-selecting a row and making sure its on the current page...

Pre-selecting a row and making sure its on the current page...

ChrisCwmbranChrisCwmbran Posts: 7Questions: 2Answers: 0
edited January 2018 in Free community support

Hi all!

I'm fairly new to both JS and JQuery, and very new to this plugin, but I must say it rocks!

The one thing I haven't managed to work out how to do, is when the table is rendered, how do I select a specific row and make sure it's on the displayed table page?

Obviously I can add the "selected" class to the row when I render the HTML, but I have the feeling this isn't the correct solution. It feels like triggering a click on the specific row using JQuery might be better, but then how do I ensure the relevant page of the data is displayed?

Thanks in advance!

Chris.

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Answers

  • kthorngrenkthorngren Posts: 21,303Questions: 26Answers: 4,947
    Answer ✓

    See if the row().show() plugin is what you ware looking for:
    https://datatables.net/plug-ins/api/row().show()

    Kevin

  • ChrisCwmbranChrisCwmbran Posts: 7Questions: 2Answers: 0

    Thanks for the link Kevin.

    I had actually located this page but I'm not sure I fully understand how to use it. I found the example a bit confusing.

  • kthorngrenkthorngren Posts: 21,303Questions: 26Answers: 4,947
    edited January 2018 Answer ✓

    Here is an example I previously built to try it out:
    http://live.datatables.net/hatojihe/3/edit

    Click the button "Find Quinn". It uses the select extension to highlight the row. You can remove .select() if you don't want to highlight the row.

    Kevin

  • ChrisCwmbranChrisCwmbran Posts: 7Questions: 2Answers: 0

    Thank you! That I understand!

    Although Im a little puzzled by why you have

    .draw(false);
    
  • kthorngrenkthorngren Posts: 21,303Questions: 26Answers: 4,947
    edited January 2018 Answer ✓

    To stay on the current page. If I just had .draw(); Datatables would display the first page. This is documented in the draw() docs.

    Kevin

  • ChrisCwmbranChrisCwmbran Posts: 7Questions: 2Answers: 0

    I almost have this working perfectly now thanks to you!

    The only problem is, if the value of variable `defaultReg' isn't in the table I get an error. Try as I might I cant get the code right to stop the error.

    function display_table() {
        $.ajax({
            type: 'POST',
            url: "./includes/modules/sec0020v101/sec0020table.php",
            data: { registration: registration },
            success:function(data) {
                $('#sec0020div1')
                          .html(data);
                table = $('#sec0020table1')
                    .DataTable({
                        select: {
                            style: 'single'
                        },
                        dom: 'Bfrtip',
                        buttons: [
                            'copyHtml5',
                            {
                                extend: 'excelHtml5',
                                orientation: 'landscape',
                                pageSize: 'A4',
                                exportOptions: {
                                    columns: ':visible'
                                }
                            },
                            'csvHtml5',
                            {
                                extend: 'pdfHtml5',
                                orientation: 'landscape',
                                pageSize: 'A4',
                                exportOptions: {
                                    columns: ':visible'
                                }
                            },
                            {
                                extend: 'print',
                                orientation: 'landscape',
                                pageSize: 'A4',
                                exportOptions: {
                                    columns: ':visible'
                                }
                            },
                            'pageLength',
                            'colvis'
                        ],
                        lengthMenu: [
                            [ 10, 25, 50, -1 ],
                            [ '10 rows', '25 rows', '50 rows', 'Show all' ]
                        ]
                    });
                if(defaultReg) {
                    table
                        .row(function ( idx, data, node ) { return data[1] === defaultReg; } )
                        .select()
                        .show()
                        .draw(false);
                        $('#sec0020navigation').find('.button-disabled')
                            .addClass('button')
                            .removeClass('button-disabled');
    
                }
            }
        });
    }
    

    That is certain to be a limitation of my poor JavaScript rather than your excellent solution!

  • kthorngrenkthorngren Posts: 21,303Questions: 26Answers: 4,947
    edited January 2018

    My approach would be to define defaultReg before the ajax call, for example:

    function display_table() {
        var defaultReg;
        $.ajax({
        ......
    

    This way the variable exists and you won't get the error defaultReg is not defined. Assuming that is the error you are getting.

    Kevin

  • ChrisCwmbranChrisCwmbran Posts: 7Questions: 2Answers: 0

    Sorry! I should have said the error is:

    datatables.js:79211 Uncaught TypeError: Cannot read property 'nTr' of undefined
        at _fnDraw (datatables.js:79211)
        at _fnReDraw (datatables.js:79316)
        at _Api.<anonymous> (datatables.js:83209)
        at _Api.iterator (datatables.js:82789)
        at _Api.<anonymous> (datatables.js:83198)
        at _Api.draw (datatables.js:82957)
        at Object.success (index.php?page=emotiveretailstock&registration=TW63CTX:249)
        at u (jquery-3.3.1.min.js:2)
        at Object.fireWith [as resolveWith] (jquery-3.3.1.min.js:2)
        at k (jquery-3.3.1.min.js:2)
    

    So it seems to be when the .draw clause is called. Im assuming that because the .row function didn't find a row, it is perhaps undefined?

  • kthorngrenkthorngren Posts: 21,303Questions: 26Answers: 4,947
    edited January 2018

    I see. I think this example change will help:
    http://live.datatables.net/gefemike/1/edit

    It tries to find the row first. If one is returned then it will show the row otherwise it does
    nothing.

    Using return data[0] === 'QuinnFlynn'; should result in no error and page 1 displayed. Changing to return data[0] === 'Quinn Flynn'; should show the page Quinn is on.

    Kevin

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