How can I use editor.dependent() to get a single value for a field instead of a select?

Gargiucn

I usually use editor.dependent() to get a value from a list box:

// JS file
...
{
    label: "Provincia",
    name: "contatti.cont_prov",
    type: "select"
},          
{
    label: "Località",
    name: "contatti.cont_loc",
    type: "select"
},
{
    label: "CAP",
    name: "contatti.cont_cap",
    type: "select"

},
...
clientiEditor.dependent( 'contatti.cont_prov', 'php/filtro_localita.php' ); 
clientiEditor.dependent( 'contatti.cont_loc', 'php/filtro_cap.php' );
...

// PHP file: filtro_localita.php
<?php
include( "DataTables.php" );

$comuni = $db
    ->select( 'comuni', ['com_nome as value','com_nome as label']
        ,['com_prov' => $_REQUEST['values']['contatti.cont_prov']] )
    ->fetchAll();

echo json_encode( [
    'options' => [
        'contatti.cont_loc' => $comuni
    ]
] );

// PHP file: filtro_cap.php
<?php
include( "DataTables.php" );

$cap = $db
    ->select( 'comuni', ['com_cap as value','com_cap as label']
        ,['com_nome' => $_REQUEST['values']['contatti.cont_loc']] )
    ->fetchAll();

echo json_encode( [
    'options' => [
        'contatti.cont_cap' => $cap
    ]
] );

<?php
>
```
But how can I get a single value for the contatti.cont_cap field instead of a list box?
I tried to write:
```
// JS file
...
{
    label: "Provincia",
    name: "contatti.cont_prov",
    type: "select"
},          
{
    label: "Località",
    name: "contatti.cont_loc",
    type: "select"
},
{
    label: "CAP",
    name: "contatti.cont_cap"
?>


},

and I modified the file filtro_cap.php in this way:
```
<?php
include( "DataTables.php" );

$cap = $db
->select( 'comuni', ['com_cap']
,['com_nome' => $_REQUEST['values']['contatti.cont_loc']] )
->fetchAll();

echo json_encode( $cap );

<?php > ``` the php file returns (for example): ``` [{"com_cap":"92100"}] ``` but my field is: contatti.cont_cap... how should i do? ?>

Thanks for your help,
Giuseppe

allan

$_REQUEST['values']['contatti']['cont_loc']]

should do it I think.

If it doesn't could you add print_r( $_REQUEST ); and show me the output?

Thanks,
Allan

Gargiucn

I try to explain myself better...
I would like to get the value for the 'contatti.cont_cap' (CAP) field without having to select it from a list box

As you can see from the image, by selecting the 'Localita' field (contatti.cont_loc) I get the value of the 'CAP' field (contatti.cont_cap) because both fields are present in the 'comuni' table (com_nome and com_cap).
I get only one 'CAP' value but I would like it to be editable and it would not look like a list box with only one value ...

Thanks,
Giuseppe

Gargiucn

I was able to get the single field value I needed.
I would just like to rewrite the same instructions with the "standard datatables syntax"...

$select = "SELECT rli_mesi FROM rlistini WHERE rli_id = ".$_POST['id']."";
$result = mysqli_query($conn, $select);
$row = mysqli_fetch_assoc($result); 
$id = $row['rli_mesi'];
echo json_encode(array("rlimesi"=>$id));    

Thanks for the help you want to give me.
Giuseppe