DataTable Showing 0 to 0 of 0 entries

DataTable Showing 0 to 0 of 0 entries

sandywicaksonosandywicaksono Posts: 5Questions: 2Answers: 0

Hi all,
i newbie in datatable, i tried somecode in a website about CRUD but i have a problem with datatable show dataentries 0 like this

and when i type in search coloumn its dissappear. like this

no error in when i see console

this is the debug

https://debug.datatables.net/ahevop

this is my code

$(document).ready(function() {
        show(); //pemanggilan fungsi tampil barang.
        var table = $('#table_id').DataTable({
            "processing": true,
            "serverSide": false,
            "stateSave": true,
        });
    });

    function show() {
        $.ajax({
            type: 'POST',
            url: '/aktivasi/getallpa/',
            dataType: 'JSON',
            success: function(data) {
                var html = '';
                var i;
                for (i = 0; i < data.length; i++) {
                    html += '<tr>' +
                        '<td>' + data[i].pa + '</td>' +
                        '<td>' + data[i].customer + '</td>' +
                        '<td>' + data[i].address + '</td>' +
                        '<td>' + data[i].sid + '</td>' +
                        '<td>' + data[i].ptl + '</td>' +
                        '<td>' + data[i].mitra + '</td>' +
                        '<td>' + data[i].date_created + '</td>' +
                        '<td class="text-center">' +
                        '<div class="list-icons">' +
                        '<div class="dropdown">' +
                        '<a href="#" class="list-icons-item" data-toggle="dropdown">' +
                        '<i class="icon-menu9"></i>' +
                        '</a>' +

                        '<div class="dropdown-menu dropdown-menu-right">' +
                        '<a data="' + data[i].sid + '" class="dropdown-item js-detail"><i class="fas fa-edit"></i> Edit</a>' +
                        '<a id="' + data[i].sid + '" class=" dropdown-item js-detail-delete"><i class="fas fa-trash"></i> Delete</a>' +
                        '</div>' +
                        '</div>' +
                        '</div>' +
                        '</td>' +
                        '<tr>'


                }
                $('#show_data').html(html);




            }



        });

    }
</script>

please refer me references or keywords to fix this

thanks :)

This question has an accepted answers - jump to answer

Answers

  • kthorngrenkthorngren Posts: 20,974Questions: 26Answers: 4,885

    The problem is you are initializing Datatables to an empty table. Next you are populating the HTML table directly which Datatables doesn't know about. Move the Datatable init code (lines 3-7) after the for loop, for example:

    ```js
    for (i = 0; i < data.length; i++) {
    html += '<tr>' +
    .....

                }
                var table = $('#table_id').DataTable({
                    "processing": true,
                    "serverSide": false,
                    "stateSave": true,
                });
                $('#show_data').html(html);
    

    ```

    Another option is to do the same but use data to add the data in place of the for loop. Use columns.data to define the columns and use columns.render to generate the HTML for the last column.

    Kevin

  • sandywicaksonosandywicaksono Posts: 5Questions: 2Answers: 0

    Hi Kevin,
    i try your code but it still no work, any idea ?
    https://debug.datatables.net/esolaf

     function show() {
                $.ajax({
                    type: 'POST',
                    url: '/aktivasi/getallpa/',
                    dataType: 'JSON',
                    success: function(data) {
                        var html = '';
                        var i;
                        for (i = 0; i < data.length; i++) {
                            html += '<tr>' +
                                '<td>' + data[i].pa + '</td>' +
                                '<td>' + data[i].customer + '</td>' +
                                '<td>' + data[i].address + '</td>' +
                                '<td>' + data[i].sid + '</td>' +
                                '<td>' + data[i].ptl + '</td>' +
                                '<td>' + data[i].mitra + '</td>' +
                                '<td>' + data[i].date_created + '</td>' +
                                '<td class="text-center">' +
                                '<div class="list-icons">' +
                                '<div class="dropdown">' +
                                '<a href="#" class="list-icons-item" data-toggle="dropdown">' +
                                '<i class="icon-menu9"></i>' +
                                '</a>' +
                                '<div class="dropdown-menu dropdown-menu-right">' +
                                '<a data="' + data[i].sid + '" class="dropdown-item js-detail"><i class="fas fa-edit"></i> Edit</a>' +
                                '<a id="' + data[i].sid + '" class=" dropdown-item js-detail-delete"><i class="fas fa-trash"></i> Delete</a>' +
                                '</div>' +
                                '</div>' +
                                '</div>' +
                                '</td>' +
                                '<tr>'
                        }
                        var table = $('#table_id').DataTable();
                        $('#show_data').html(html);
                    }
    
    
    
                });
    
            }
    
  • colincolin Posts: 15,232Questions: 1Answers: 2,597

    We're happy to take a look, but as per the forum rules, please link to a test case - a test case that replicates the issue will ensure you'll get a quick and accurate response. Information on how to create a test case (if you aren't able to link to the page you are working on) is available here.

    Cheers,

    Colin

  • kthorngrenkthorngren Posts: 20,974Questions: 26Answers: 4,885
    Answer ✓

    Sorry I reversed lines 33 and 34. It should be:

                       $('#show_data').html(html);
                       var table = $('#table_id').DataTable();
    

    Kevin

  • sandywicaksonosandywicaksono Posts: 5Questions: 2Answers: 0

    Hi Kevin,
    Thanks, it works :smile:

    Sandy Wicaksono

This discussion has been closed.