Problem with Data shown in table only
Problem with Data shown in table only
info@invisiblefarm.it
Posts: 11Questions: 4Answers: 0
in Editor
Error messages shown: Unable to cast value to be String
Description of problem:
Hi, I'm usign Datatables Editor .NET Framework
I need to reproduce this example but I've got always "Unable to cast value to be String"
I don't use a fixed Model but create field on fly; this is my controller class
private ActionResult DoAction(string table, System.Web.HttpRequest request, string action = null)
{
bool action_defined = !string.IsNullOrWhiteSpace(action);
GestioneDizionarioModel page_model = new GestioneDizionarioModel(table);
DtResponse response = null;
using (Database db = DbExtensions.GetDatabaseConnection())
{
Editor editor = new Editor(db, table, "chiave");
if (!string.IsNullOrWhiteSpace(action))
{
editor.Field(
new Field("last_update", typeof(DateTime), null)
.Set(Field.SetType.Both)
.DbType(System.Data.DbType.DateTime)
.GetFormatter(Format.DateSqlToFormat(Format.DATE_ISO_822))
.SetFormatter(Format.DateFormatToSql("yyyy-MM-dd HH:mm:ss"))
);
}
foreach (FieldInformation field in page_model.dizionarioModel.fields)
{
editor.Field(new Field(field.name));
}
if (action_defined && action.Equals("remove"))
{
// Disallow delete just in case anyone uses the API to do it
editor.PreRemove += (sender, args) => args.Cancel = true;
}
editor.Process(request);
response = editor.Data();
}
if (action_defined)
{
DizionariCondivisiLogger.LogUpdateStatisticheDizionario(table, DbExtensions.GetTableRowsCount(table));
}
return Json(response);// new { response = response });
}
How can resolve? Thanks!
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Answers
You'll need to use a string type for the DateTime I'm afraid. The problem with using
DateTime
is that it can't be directly represented in JSON, which we use as the transport format.Regards,
Allan
I should note that you can still use
DateTime
in the db!!! Only in C#-land does it need to be a string.I read a lot of time .NET Editor example "Table only data" and I found only now that there is a trigger on table users
I'm going to implement this solution,
thanks