i am getting this error

umaeswara

DataTables warning: table id=DataTables_Table_0 - Incorrect column count. For more information about this error, please see https://datatables.net/tn/18
can you please suggest, the remedy.
thanks,
Uma-

umaeswara

i dont have any header in my table.
here is the table
Unnamed: 0 439
company One1
Price 436.23
Change% 4.34

umaeswara

if I want to add table header using my js file, but this js file is used by many other tables.
how to check table which doesnt have deader and add an invisible table header. i was thinking columnDerfs with visible false, and th cells as first row. is that possible, if so how?

kthorngren

The columns.title option can be used to create table headers but hey won't be hidden. However you could use CSS to hide them.

You can create them in HTML and use something like style="display: none;" or better CSS to hide the th.

Or you can use Javascript to jQuery methods to add the headers to the table before initializing Datatables. Use Stack Overflow to find the method that works for your situation.

i was thinking columnDerfs with visible false,

This will hide the whole column not just the header.

Kevin

umaeswara

Ok, thanks. I used java method to append header cells.
if ($("table thead").length === 0) { ... } if anyone interested to solve similar problem.

BTW, for the question if JS is common for all the tables which are in different pages.
var table = $("table").DataTable({ ..... });
inside this can I check table id etc? table data conditions to set some columnDefs ?

thanks,
Uma-

allan

inside this can I check table id etc? table data conditions to set some columnDefs ?

Inside the configuration object no. Outside yes. Here is one way of doing it:

$('table').each(function () {
  let options = {
    // defaults
    scrollX: true
  };

  // Table overrides
  if (this.id === 'myTable') {
    options.scrollX = false;
  }
  else if (this.id === 'thatTable') {
    // ...
  }

  $(this).DataTable(options);
});

Allan

umaeswara

thanks, let me try and come back. I have several tables and each have different kind of options.