Replies

• bindrid Posts: 730Questions: 0Answers: 119

  March 2017

  Your url is in an if statement. If it evaluates false, the url will be undefinded.

  Your data section does not return anything but undefined since it does not return anything.

  And you don't need both a url with the parameters attached and a data that also returns parameters.
• nessinits Posts: 86Questions: 27Answers: 0

  March 2017

  Hi,

  Thanks for your response.

  It doesn't evaluate false, because it can only be posted when an emloyee is selected.

  I don't understand your emark on the data section. Mainly the part where you say: since it does not return anything. Could you be more specific why?

  I tried both ways because of I want to resolve this one way or the other. The data way is the cleanest, of course.

  Hope you can help me a little more.

  Kind regards,
  nessinits
• tangerine Posts: 3,365Questions: 39Answers: 395

  March 2017

         data: function ( d ) {
              var selected = employeetable.row( { selected: true } );
   
              if ( selected.any() ) {
                  d.foreign_id = selected.data().employee_id;
              }
          }
  

  That function does not return anything, as @bindrid says.
• nessinits Posts: 86Questions: 27Answers: 0

  March 2017

  How is that different from the example from the website below:

  var editor = new $.fn.Editor( {
      ajax:  {
          url: 'php/staff.php',
          data: function ( d ) {
              d.user_id = $('#user_id').val();
          }
      },
      table: '#myTable'
  } );
  
• allan Posts: 63,535Questions: 1Answers: 10,475 Site admin

  March 2017

  I don't understand your emark on the data section. Mainly the part where you say: since it does not return anything. Could you be more specific why?

  That statement wasn't quite accurate - although I completely concur with the point about the url being undefined. It should at least point at an error script I would say.

  The way the ajax.data option works as a function is that you can modify the object passed in and that will be used. Alternatively, you can return an object and DataTables / Editor will use that instead. Both are valid.

  As you can see, I tried to use a function to build up the url dynamically

  I don't think you can define the URL as a function in jQuery and that isn't a feature that DataTables adds.

  but I need that data also while uploading the file

  This with the upload field type is it? You can give it its own ajax option that submit parameters specifically for that. However, the ajax.data function should be used. Could you give me a link to the page please?

  Allan