Answers

• colin Posts: 15,240Questions: 1Answers: 2,599

  October 2018

  Hi @fael_christofano ,

  It might be better to say what you're trying to do, because as you said, the drawCallback is unlikely to be right place.

  If the buttons affect the drawing of the table, or the data that you want from the server, the best bet would be to call ajax.reload() in the click event for the radio button. You could send the value of the radio button, or some other logic based on the selection, to the server in ajax.data. This would force a reload based on the selection.

  Hope that helps,

  Cheers,

  Colin
• colin Posts: 15,240Questions: 1Answers: 2,599

  October 2018

  Hi @fael_christofano ,

  As I said, you can use ajax.data for that. Set it in the main ajax declaration in the table initialisation.

  Cheers,

  Colin
• fael_christofano Posts: 13Questions: 2Answers: 0

  October 2018

  I Edited my question, did you see?
• fael_christofano Posts: 13Questions: 2Answers: 0

  October 2018 edited October 2018

  $(document).ready( function () {
  var table = $('#tabelaVagas').DataTable({
         "processing": true,
           "serverSide": true,    
           "ajax": {
                   url: "carregar-vagas.php",
                   data: {$("input[name='rAtivo']:checked").val()},
                   type: "POST",
                   error: function (){
                       $('#post_list_processing').css('display','none');
                   }
  })
  });
  
  $("input[name='rAtivo']").on('click', function(){
          event.preventDefault();    
          table.reload();
  })
  
• colin Posts: 15,240Questions: 1Answers: 2,599

  October 2018 edited October 2018 Answer ✓

  If you look at the examples on the page ajax.data, you'll see they're setting a value that goes into the JSON, you're not doing that.

  Your line 7 should be something like:

  data: {
     checkValue = $("input[name='rAtivo']:checked").val()
  }
  

  You would then access checkValue on the server.
• fael_christofano Posts: 13Questions: 2Answers: 0

  October 2018

  Perfect Colin, but I modified this code, stayed like this

  data: function ( d ) {
  d.rAtivo = $("input[name='rAtivo']:checked").val();
  },