Reporting Problem
Reporting Problem
Hello, I have a problem of index not defined and I do not know how
`<?php
$servername = "localhost";
$username = "root";
$password = "Mm101010";
$dbname = "smartphone";
$conn = mysqli_connect($servername, $username, $password, $dbname) or die("Connection failed: " . mysqli_connect_error());
$requestData = $_REQUEST;
$columns = array(
0 => 'USER_ID',
1 => 'Nom',
2 => 'Prenom',
3 => 'Num_SIM',
4 => 'PIN_Terminal',
5 => 'PIN_SIM',
6 => 'Num_IMEI',
7 => 'Date_Debut',
8 => 'Date_Fin',
8 => 'Vitre',
10 => 'Coque',
11 => 'Support_Vehicule',
12 => 'Actif',
13 => 'Statut'
);
$sql = "SELECT Or_Affectation ";
$sql.=" FROM vu_affect_empl";
$query=mysqli_query($conn, $sql) or die("Affectation.php: get employees");
$totalData = mysqli_num_rows($query);
$totalFiltered = $totalData;
$sql = "SELECT Or_Affectation, USER_ID, Nom, Prenom, Num_SIM, PIN_Terminal, PIN_SIM, Num_IMEI, Date_Debut, Date_Fin, Vitre, Coque, Support_Vehicule, Actif, Statut ";
$sql.=" FROM vu_affect_empl WHERE 1=1";
if( !empty($requestData['search']['value']) ) {
$sql.=" AND ( USER_ID LIKE '".$requestData['search']['value']."%' ";
$sql.=" OR Num_SIM LIKE '".$requestData['search']['value']."%' ";
$sql.=" OR Nom LIKE '".$requestData['search']['value']."%' )";
}
$query=mysqli_query($conn, $sql) or die("Affectation.php: get employees");
$totalFiltered = mysqli_num_rows($query);
$query=mysqli_query($conn, $sql) or die("Affectation.php: get employees");
$data = array();
$i=1+$requestData['start'];
while( $row=mysqli_fetch_array($query) ) {
$nestedData=array();
$nestedData[] = "<input type='checkbox' class='deleteRow' value='".$row['Or_Affectation']."' /> #".$i ;
$nestedData[] = $row["USER_ID"];
$nestedData[] = $row["Nom"];
$nestedData[] = $row["Prenom"];
$nestedData[] = $row["Num_SIM"];
$nestedData[] = $row["PIN_Terminal"];
$nestedData[] = $row["PIN_SIM"];
$nestedData[] = $row["Num_IMEI"];
$nestedData[] = $row["Date_Debut"];
$nestedData[] = $row["Date_Fin"];
$nestedData[] = $row["Vitre"];
$nestedData[] = $row["Coque"];
$nestedData[] = $row["Support_Vehicule"];
$nestedData[] = $row["Actif"];
$nestedData[] = $row["Statut"];
$data[] = $nestedData;
$i++;
}
$json_data = array(
"draw" => intval( $requestData['draw'] ),
"recordsTotal" => intval( $totalData ),
"recordsFiltered" => intval( $totalFiltered ),
"data" => $data
);
echo json_encode($json_data);
<?php > ` Here is the error image ?>thx
Answers
Have you enabled
serverSide
in your DataTables initialisation?Allan
yes, But I do not see what identified the variable with respect to the variable
I don't really understand I'm afraid. The
serverSide
option tells DataTables to enter into server-side processing mode, whereby it will send the parameters described here to the server with each request (defined byajax
).Allan